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radius then the object becomes a Schwarzschild black hole (see Chapter 11). For
the remainder of this chapter, however, we will restrict our attention to the region
r > 2GM/c2 . We will often use the shorthand в‰Ў GM/c2 when writing down
this metric.

9.3 BirkhoffвЂ™s theorem
If we do not demand that our original metric is static (or stationary) but only that
it is isotropic, then we would substitute the more general form (9.3),

ds2 = A t r dt2 в€’ B t r dr 2 в€’ r 2 d + sin2 d
2 2

into EinsteinвЂ™s empty-space field equations R = 0 in order to determine the
functions A t r and B t r . On repeating our earlier analysis, we would find
some additional non-zero connection coefficients and components of the Ricci
tensor. However, on solving this new set of equations, one discovers that the
resulting metric must still be the Schwarzschild metric (9.12). Thus, we obtain
BirkhoffвЂ™s theorem, which states that the spacetime geometry outside a general
spherically symmetric matter distribution is the Schwarzschild geometry.
This is an unexpected result because in Newtonian theory spherical symmetry
has nothing to do with time dependence. This highlights the special character of
the empty-space Einstein equations and of the solutions they admit. In particular,
BirkhoffвЂ™s theorem implies that if a spherically symmetric star undergoes strictly
radial pulsations then it cannot propagate any disturbance into the surrounding
space. Looking ahead to Chapter 18, this means that a radially pulsating star
cannot emit gravitational waves.
One can show that the converse of BirkhoffвЂ™s theorem is not true, i.e. a matter
distribution that gives rise to the Schwarzschild geometry outside it need not be
spherically symmetric. Indeed, some specific counter-examples are known.

9.4 Gravitational redshift for a fixed emitter and receiver
We begin our discussion of the physics in the vicinity of a spherical mass M by
considering the phenomenon of gravitational redshift. In particular, we consider
the specific example of an emitter, at fixed spatial coordinates rE E E ,
which emits a photon that is received by an observer at fixed spatial coordinates
rR R R . If tE is the coordinate time of emission and tR the coordinate time
203
9.4 Gravitational redshift for a fixed emitter and receiver

D (tR + в€†tR, rR, ОёR, П†R)

ic
es
od
ge
l
ul
N
C (tR , rR, ОёR, П†R)

sic
B (tE + в€†tE, rE, ОёE, П†E)

de
eo
lg
ul
N
A (tE , rE, ОёE, П†E)

at fixed at fixed
(rE, ОёE, П†E) (rR, ОёR, П†R)

Figure 9.1 Schematic illustration of the emission and reception of two light signals.

of reception then the photon travels from the event tE rE E E to the event
tR rR R R along a null geodesic in the Schwarzschild spacetime. This is
illustrated schematically in Figure 9.1, which also shows a second photon, emitted
at a later coordinate time tE + tE and received at tR + tR .
In Appendix 9A we present an approach for calculating gravitational redshifts
in more general situations. Nevertheless, in this simple case, it is instructive to
derive the result in a more elementary manner: we need only use the fact that the
photon geodesic is a null curve.3 Thus ds2 = 0 at all points along it, and from the
Schwarzschild metric (9.12), we find that

в€’1
2 2
1в€’ dt = 1 в€’ dr 2 + r 2 d + r 2 sin2 d
2 2 2 2
c
r r

where we have written в‰Ў GM/c2 . Let us consider the first signal. Thus, if is
some affine parameter along the null geodesic then we have

в€’1/2 1/2
dxi dxj
1 2
dt
= 1в€’ в€’gij
d c r dd

3
This approach is based on that presented in J. Foster & J. D. Nightingale, A Short Course in General Relativity,
Springer-Verlag, 1995.
204 The Schwarzschild geometry

where as before we use the notation x = t r , the g are the components
of the Schwarzschild metric and Latin indices run from 1 to 3. On integrating,
we obtain
в€’1/2 1/2
dxi dxj
1 2
R
tR в€’ tE = 1в€’ в€’gij d
c r dd
E

where E is the value of at emission and R the value at reception. The
hand side depends only on the path through space. Thus, for a spatially fixed
emitter and receiver, tR в€’ tE is the same for all signals sent. Thus the coordinate
time difference tE separating events A and B is equal to the coordinate time
tR between events C and D,
tR = tE
Now let us consider the proper time intervals along the worldlines of the emitter
and receiver between each pair of events. Along both the emitterвЂ™s and receiverвЂ™s
worldlines, dr = d = d = 0. Thus, from the Schwarzschild line element (9.12),
in both cases
2
c2 d 2 в‰Ў ds2 = c2 1 в€’ dt2
r
Moreover, in each case r is constant along the worldline, so we can immediately
integrate this equation to obtain
1/2 1/2
2 2
= 1в€’ = 1в€’
and
tE tR
E R
rE rR
tR = tE , we find that
Thus, since
1/2
1 в€’ 2 /rR
R
=
1 в€’ 2 /rE
E
which forms the basis of the formula for gravitational redshift. If we think of the
two light signals as, for example, the two wavecrests of an electromagnetic wave,
then it is clear that this ratio must also be the ratio of the period of the wave
as observed by the receiver and emitter respectively. Thus the frequencies of the
photon as measured by each observer are related by

1/2
1 в€’ 2GM/ rE c2
R
= (9.13)
1 в€’ 2GM/ rR c2
E

which shows that if rR > rE . The photon redshift z is defined by
<
R E
в€’1
1+z = R/ E
205
9.5 Geodesics in the Schwarzschild geometry

very easily to any spacetime in which we can choose coordinates such that the
spacetime is stationary 0 g = 0 and g0i x = 0. In this case,

ds2 = g00 x dt2 + gij x dxi dxj

where, as indicated, all the metric components are independent of t. By repeating
the above derivation for an emitter and observer at fixed spatial coordinates in
this more general spacetime, we easily find that

1/2
gx
= 00 E
R
(9.14)
g00 xR
E

The derivations presented here depend crucially upon the fact that the emitter
and receiver are spatially fixed. However, this is not often physically realistic.
For example, we might want to calculate the gravitational redshift of a photon
if the emitter or receiver (or both) are in free fall or moving in some arbitrary
manner. A method for calculating redshifts in such general situations is given in
Appendix 9A. In order to use this formalism, however, we require knowledge
of the paths followed by freely falling particles and photons. Therefore, we now
consider geodesics in the Schwarzschild geometry.

9.5 Geodesics in the Schwarzschild geometry
In deriving the Schwarzschild line element,
в€’1
2 2
ds = c 1в€’ dt в€’ 1 в€’ dr 2 в€’ r 2 d в€’ r 2 sin2 d
2 2 2 2 2
(9.15)
r r
we also calculated the connection coefficients for this metric. Thus we could
now write down the geodesic equations for the Schwarzschild geometry in the
form
d2 x dx dx
+ =0
d2 dd
where is some affine parameter along the geodesic x . It is more instruc-
tive, however, to obtain the geodesic equations using the very neat вЂ˜LagrangianвЂ™
procedure discussed in Chapter 3.
Thus, let us consider the вЂ˜LagrangianвЂ™ L = g x x , where x в‰Ў dx /d .
Л™Л™ Л™
Using (9.15), L is given by
в€’1
2 2
r 2 в€’ r 2 Л™ 2 + sin2 Л™2
Л™2
L=c 1в€’ t в€’ 1в€’ Л™
2
(9.16)
r r
206 The Schwarzschild geometry

The geodesic equations are then obtained by substituting this form for L into the
the EulerвЂ“Lagrange equations
d L L
в€’ =0
Л™
d x x
Performing this calculation, we find that the four resulting geodesic equations (for
= 0 1 2 3) are given by
2
Л™
1в€’ t=k (9.17)
r
в€’1 в€’2
c2 2
2 2
r 2 в€’ r Л™ 2 + sin2 Л™2 = 0
Л™
1в€’ r + 2 t в€’ 1в€’
ВЁ Л™ (9.18)
2
r r r r

ВЁ + 2 r Л™ в€’ sin cos Л™ 2 = 0
Л™ (9.19)
r
r 2 sin2 Л™ = h (9.20)

In (9.17) and (9.20) respectively, the quantities k and h are constants. These two
equations are derived immediately since L is not an explicit function of t or .
We see immediately that = /2 satisfies the third geodesic equation (9.19).
Because of the spherical symmetry of the Schwarzschild metric we can therefore,
with no loss of generality, confine our attention to particles moving in the вЂ˜equato-
rial planeвЂ™ given by = /2. In this case our set of geodesic equations reduces to
2
Л™
1в€’ t=k (9.21)
r
в€’1 в€’2
c2 2
2 2
r2 в€’ r Л™ 2 = 0
Л™
1в€’ r + 2 t в€’ 1в€’
ВЁ Л™ (9.22)
r2
r r r
r2 Л™ = h (9.23)

These equations are valid for both null and non-null affinely parameterised
geodesics. In each of these cases, however, it is easier to replace the rather
complicated r-equation (9.22) by a first integral of the geodesics equations. For
a non-null geodesic this first integral is simply

g x x = c2
Л™Л™ (9.24)

whereas for a null geodesic it is

g x x =0
Л™Л™ (9.25)

Before going on to discuss separately non-null and null geodesics in the equa-
torial plane = /2, it is instructive to discuss the physical interpretation of the
207
9.6 Trajectories of massive particles

constants k and h. One can arrive at equations (9.21) and (9.23) simply by using
the fact that the components p0 and p3 of a particleвЂ™s 4-momentum are conserved
along geodesics since L does not depend explicitly on t and (remember that p
is proportional to the tangent vector to the geodesic at each point). For notational
simplicity, for a massive particle, we shall take the particle to have unit rest
mass and choose the affine parameter to be the particleвЂ™s proper time , so that
p = x . Similarly, for a massless particle we are free to choose an appropriate
Л™
affine parameter along the null geodesic, once again such that p = x . Thus, for
Л™
= /2 we may write

2
Л™ Л™
p0 = g00 t = c2 1 в€’ t = kc2 (9.26)
r
p3 = g33 Л™ = в€’r 2 Л™ = в€’h (9.27)

where in the last equality on each line we have defined the constants in a manner
that coincides with (9.21) and (9.23). Let us first consider the constant k. If, at some
event, an observer with 4-velocity u encountered a particle with 4-momemtum p
then he would measure the particleвЂ™s energy to be

E = pВ·u = p u

For an observer at rest at infinity we have u = 1 0 0 0 and so E = p0 = kc2
(which is conserved along the particle geodesic). Thus we may take k = E/c2 ,
where E is the total energy of the particle in its orbit. Since for massive particles
we have assumed unit mass, in the general case we have k = E/ m0 c2 , where
m0 is the rest mass of the particle. For the constant h, we can see immediately
from (9.27) that it equals the specific angular momentum of the particle and that
(as result of the choice of signature for the metric) p3 is equal to minus the
specific angular momentum. Finally, we note that the results (9.17вЂ“9.20) can also
be derived using the alternative form (3.56) of the geodesic equations, which may
be written

p= 1
(9.28)
g pp
2

9.6 Trajectories of massive particles
The trajectory of a massive particle is a timelike geodesic. Considering motion in
the equatorial plane, we replace the geodesic equation (9.22) by (9.24), where g
is taken from (9.15) with = /2. Moreover, since we are considering a timelike
geodesic we can choose our affine parameter to be the proper time along the
208 The Schwarzschild geometry

path. Thus we find that the worldline x of a massive particle moving in the
equatorial plane of the Schwarzschild geometry must satisfy the equations
2
Л™
1в€’ t=k (9.29)
r
в€’1
2 2
r 2 в€’ r 2 Л™ 2 = c2
Л™2
1в€’ t в€’ 1в€’ Л™
2
(9.30)
c
r r
r2 Л™ = h (9.31)
By substituting (9.29) and (9.31) into (9.30), we obtain the combined вЂ˜energyвЂ™
equation for the r-coordinate,

h2 2GM 2GM
r + 2 1в€’ 2
Л™ в€’ = c 2 k2 в€’ 1
2
(9.32)
r cr r

where we have written = GM/c2 . We shall use this вЂ˜energyвЂ™ equation to discuss
radial free fall and the stability of orbits. Note that the right-hand side is a constant
of the motion. We can verify the physical meaning of the constant k by noting
that E в€ќ k. The constant of proportionality is fixed by requiring that, for a particle
at rest at r = , we have E = m0 c2 . Letting r в†’ and r = 0 in (9.32), we thus
Л™
2 = 1. Hence, as previously, we must have k = E/ m c2 , where E is
require k 0
the total energy of the particle in its orbit.
A second useful equation, which enables us to determine the shape of a particle
orbit (i.e. r as a function of ), may be found by using h = r 2 Л™ to express r in Л™
the energy equation (9.32) as
dr dr d h dr
= =2
d dd rd
We thus obtain
2
h2 2GM 2GMh2
h dr
+ 2 = c k в€’1 + + 23
22
r2 d r r cr
If we make the substitution u в‰Ў 1/r that is usually employed in Newtonian orbit
calculations, we find that
2
c2 2 2GMu 2GMu3
du
+u = 2 k в€’1 + +
2
h2 c2
d h
We now differentiate this equation with respect to to obtain finally

d2 u GM 3GM
+ u = 2 + 2 u2 (9.33)
d2 h c
209
9.7 Radial motion of massive particles

In Newtonian gravity, the equations of motion of a particle of mass m in the
equatorial plane = /2 may be determined from the Lagrangian
GMm
L = 2 m r2 + r2 Л™ 2 +
Л™
1
r
From the EulerвЂ“Lagrange equations we have

r2 Л™ = h
h GM
r=
ВЁ в€’2
r3 r
where the integration constant h is the specific angular momentum of the particle.
If we now substitute u = 1/r and eliminate the time variable, the Newtonian
equation of motion for planetary orbits is obtained:

d2 u GM
+u = 2 (9.34)
d2 h
We must remember, however, that in this equation u = 1/r, where r is the radial
distance from the mass, whereas in (9.33) r is a radial coordinate that is related
to distance through the metric. Nevertheless, the forms of the two equations are
very similar except for the extra term 3GMu2 /c2 in (9.33). We note that this term
correctly tends to zero as c в†’ .
Two interesting special cases of massive-particle orbits are worth investigating
in detail, namely radial motion and motion in a circle.

9.7 Radial motion of massive particles
is constant, which implies that h = 0. Thus, (9.32) reduces to
2GM
r 2 = c 2 k2 в€’ 1 +
Л™ (9.35)
r
Л™
Differentiating this equation with respect to and dividing through by r gives
GM
r =в€’
ВЁ (9.36)
r2
which has precisely the same form as the corresponding equation of motion in
Newtonian gravity. This does not imply, however, that general relativity and
Newtonian gravity predict the same physical behaviour. It should be remem-
bered that in (9.36) the coordinate r is not the radial distance, and dots indicate
derivatives with respect to proper time rather than universal time.
210 The Schwarzschild geometry

As a specific example, consider a particle dropped from rest at r = R. From
(9.35) we see immediately that k2 = 1 в€’ 2GM/ c2 R , so (9.35) can be written
Л™
r2 11
= GM в€’ (9.37)
2 rR
This has the same form as the Newtonian formula equating the gain in kinetic
energy to the loss in gravitational potential energy for a particle (of unit mass)
falling from rest at r = R. This provides a useful way to remember this equation,
but the different meanings of r and of the dot should again be borne in mind.
We could continue our analysis of this quite general situation, but we can
illustrate the main physical points by considering a particle dropped from rest at
infinity. In this case k = 1 and the algebra is much less complicated. Thus, setting
k = 1 in the geodesic equation (9.29) and in (9.35), we obtain
в€’1
2
dt
= 1в€’ (9.38)
d r
1/2
2 c2
dr
=в€’ (9.39)
d r
where in (9.39) we have taken the negative square root. These equations form the
basis of our discussion of a radially infalling particle dropped from rest at infinity.
From these equations we see immediately that the components of the 4-velocity
of the particle in the t r coordinate system are simply
в€’1 1/2
2 c2
2
dx
в‰Ў = 1в€’ в€’ 00
u
d r r

Equation (9.39) determines the trajectory r . On integrating (9.39) we imme-
diately obtain
3
r3
2 2
r0
= в€’
2 c2 3 2 c2
3
where we have written the integration constant in a form such that = 0 at r = r0 .
Thus is the proper time experienced by the particle in falling from r = r0 to a
Instead of parameterising the worldline in terms of the proper time , we can
alternatively describe the path as r t , thereby mapping out the trajectory of the
particle in the t r coordinate plane. This is easily achieved by writing
1/2
2 c2 2
dr dr d
= =в€’ 1в€’ (9.40)
dt d dt r r
211
9.7 Radial motion of massive particles

On integrating, we find
вЋ› вЋћ
3
r3 вЋ  4
2вЋќ r0 r0 r
t= в€’ + в€’
2 c2 2 c2
3 2 2
c

+1 в€’1
r/ 2 r0 / 2
2
+ ln
в€’1 +1
c r/ 2 r0 / 2
where the choice of the integration constant gives t = 0 at r = r0 .
In particular we note that
3
2 r0
в†’ as r в†’ 0
2 c2
3
tв†’ as r в†’ 2
Evidently, the particle takes a finite proper time to reach r = 0. When the worldline
is expressed in the form r t , however, we see that r asymptotically approaches 2
as t в†’ . Since the coordinate time t corresponds to the proper time experienced
by a stationary observer at large radius, we must therefore conclude that, to such
an observer, it takes an infinite time for the particle to reach r = 2 . We return
to this point later.
It is interesting to ask what velocity a stationary observer at r measures for
the infalling particle as it passes. From the Schwarzschild metric (9.15) we see
that, for a stationary observer at coordinate radius r, a coordinate time interval dt
corresponds to a proper time interval
1/2
2
dt = 1 в€’ dt
r
Similarly, a radial coordinate separation dr corresponds to a proper radial distance
measured by the observer equal to
в€’1/2
2
dr = 1 в€’ dr
r
Thus the velocity of the radially infalling particle, as measured by a stationary
observer at r, is given by
в€’1 1/2
2 c2
2
dr dr
= 1в€’ =в€’ (9.41)
dt r dt r
Thus we find the rather surprising result that, as the particle approaches r = 2 ,
a stationary observer at that radius observes that the particleвЂ™s velocity tends to c.
We note that the equation (9.41) is only physically valid for r > 2 since, as we
shall see, it is impossible to have a stationary observer at r в‰¤ 2 .
212 The Schwarzschild geometry

9.8 Circular motion of massive particles
For circular motion in the equatorial plane we have r = constant, and so r = r = 0.
Л™ВЁ
Setting u = 1/r = constant in the вЂ˜shapeвЂ™ equation (9.33) we have
GM 3GM 2
u= + 2u
h2 c
from which we find that
c2 r 2
h=2
r в€’3
Putting r = 0 in the energy equation (9.32) and substituting the above expression
Л™
2 allows us to identify the constant k:
for h
1 в€’ 2 /r
k= (9.42)
1 в€’ 3 /r 1/2
The energy of a particle of rest mass m0 in a circular of radius r is then given by
E = km0 c2 . We can use this result to determine which circular orbits are bound.
For this we require E < m0 c2 , so the limits on r for the orbit to be bound are
given by k = 1. This yields
1 в€’ 2 /r = 1 в€’ 3 /r
2

which is satisfied when r = 4 or r = . Thus, over the range 4 < r < ,
circular orbits are bound. A plot of E/ m0 c2 as a function of r/ is shown in
Figure 9.2.

1.1

1.05
c2)
E / (m0

1

0.95

4 6 8 10 12 14 16 18 20
r/Вµ

Figure 9.2 The variation of k = E/ m0 c2 as a function of r/ for a circular
orbit of a massive particle in the Schwarzschild geometry.
213
9.9 Stability of massive particle orbits

We can obtain another useful result by substituting our expression for h2 into
the geodesic equation r 2 Л™ = h; then we can write
2
c2
d
=2
r r в€’3
d
The significance of this equation is that it cannot be satisfied for circular orbits
with r < 3 . Such orbits cannot be geodesics (since they do not satisfy the
geodesic equations) and so cannot be followed by freely falling particles. Thus,
according to general relativity a free massive particle cannot maintain a circular
orbit with r < 3 around a spherical massive body, no matter how large the
angular momentum of the particle. This is very different from Newtonian theory.
It is also useful to calculate the expression for d /dt, which is given by
2 2 2
1 в€’ 2 /r 2 c2 GM
d dd d
= = = 3= 3
k2
dt d dt d r r
This expression is exactly the same as the Newtonian expression for the period
of a circular orbit of radius r. Although we cannot say that r is the radius of
the orbit in the relativistic case, we see that the spatial distance travelled in one
complete revolution is 2 r, just as in the Newtonian case.

9.9 Stability of massive particle orbits
The above analysis appears to suggest that the closest bound circular orbit around
a massive spherical body is at r = 4 . However, we have not yet determined
whether this orbit is stable.
In Newtonian dynamics the equation of motion of a particle in a central potential
can be written
1 dr 2
+ Veff r = E
2 dt
where Veff r is the effective potential and E is the total energy of the particle
per unit mass. For an orbit around a spherical mass M, the effective potential is
h2
GM
Veff r = в€’ +2 (9.43)
2r
r
where h is the specific angular momentum of the particle. This effective potential
is shown in Figure 9.3. It can be seen that bound orbits have two turning points
and that a circular orbit corresponds to the special case where the particle sits at
the minimum of the effective potential. Furthermore one sees that, in Newtonian
dynamics, a finite angular momentum provides an angular momentum barrier
preventing a particle reaching r = 0. This is not true in general relativity.
214 The Schwarzschild geometry

V(r)
effective potential

unbound orbit

r

elliptical orbit

circular orbit

вЂ“GM
r

Figure 9.3 The Newtonian effective potential for h = 0, showing how an angular
momentum barrier prevents particles reaching r = 0.

In general relativity, the вЂ˜energyвЂ™ equation (9.32) for the motion of a particle
around a central mass can be written
2
h2 c2 c2 2
1 2
dr
+ 2 1в€’ в€’ = k в€’1
2 2r 2
d r r
where we recall that the constant k = E/ m0 c2 . Thus in general relativity we
identify the effective potential per unit mass as
c2 h2 h2
r =в€’ + 2в€’ 3 (9.44)
Veff
2r
r r
which has an additional term proportional to 1/r 3 as compared with the Newtonian
case (9.43). Remembering that = GM/c2 , we see that (9.44) reduces to the
form (9.43) in the non-relativistic limit c в†’ .
Figure 9.4 shows the general relativistic effective potential for several values of
ВЇ
h в‰Ў h/ c . The dots indicate the locations of stable circular orbits, which occur
at the local minimum of the potential. The local maxima in the potential curves
ВЇ
are the locations of unstable circular orbits. For any given value of h, circular
orbits occur where dVeff /dr = 0. Differentiating (9.44) gives
c2 h2 3 h2
dVeff
= 2 в€’ 3+ 4
dr r r r
and so the extrema of the effective potential are located at the solutions of the
c2 r 2 в€’ h2 r + 3 h2 = 0
215
9.9 Stability of massive particle orbits

0.1

0.05
4.5

0
4.0
Veff /c 2
3.75
вЂ“ 0.05
2*(3)1/2

вЂ“ 0.1 h=0

вЂ“ 0.15
5 10 15 20 25
r /Вµ

Figure 9.4 The general relativistic effective potential plotted for several values
ВЇ
of the angular momentum parameter h.

which occur at
h
r= h В± h2 в€’ 12 2 c2
2
2c
в€љ в€љ
We note, in particular, that if h = 12 c = 2 3 c then there is only one
extremum, and there are no turning points in the orbit for lower values of h. The
significance of this result is that the innermost stable circular orbit has
6GM
rmin = 6 =
c2
в€љ
This orbit, with r = 6 and h/ c = 2 3, is unique in satisfying both
dVeff /dr = 0 and d2 Veff /dr 2 = 0, the latter being the condition for marginal
stability of the orbit.
The existence of an innermost stable orbit has some interesting astrophysical
consequences. Gas in an accretion disc around a massive compact central body
settles into circular orbits around the compact object. However, the gas slowly
loses angular momentum because of turbulent viscosity (the turbulence is thought
to be generated by magnetohydrodynamic instabilities). As the gas loses angular
momentum it moves slowly inwards, losing gravitational potential energy and
heating up. Eventually it has lost enough angular momentum that it can no longer
follow a stable circular orbit, and so it spirals rapidly inwards onto the central
object.
We can make an estimate of the efficiency of energy radiation in an accretion
disc. The maximum efficiency is of the order of the вЂ˜gravitational binding energyвЂ™
216 The Schwarzschild geometry

at the innermost stable circular orbit (i.e. the energy E lost as the particle moves
from infinity to the innermost orbit) divided by the rest mass energy of the particle.
Setting r = 6 in (9.42) and remembering that k = E/ m0 c2 , we find that
в€љ
22
E
= в‰€ 0 943
m0 c2 3
Thus the maximum radiation efficiency of the accretion disc is

в‰€ 1 в€’ 0 943 = 5 7%
acc

Thus, an accretion disc around a highly compact astrophysical object can convert
perhaps a few percent of the rest mass energy of the gas into radiation; this may be
compared with the efficiency of nuclear burning of hydrogen to helium (26 MeV
per He nucleus),
в€ј 0 7%
nuclear

Accretion discs are therefore capable of converting rest mass energy into radiation
with an efficiency that is about 10 times greater than the efficiency of the nuclear
burning of hydrogen. The вЂ˜accretion powerвЂ™ of highly compact objects (such as
black holes) cause some of the most energetic phenomena known in the universe.
A physically intuitive picture of a non-circular orbit and the capture of a particle
with non-zero angular momentum h may be obtained by differentiating the energy

12

10

8

6

4

2

0
вЂ“5 0 5 10 15 20
вЂ“2

вЂ“4

Figure 9.5 Orbit for a particle projected azimuthally from r = 20GM/c2 with
в€љ
h = 3 5GM/c. A circular orbit would require h = 20/ 17 GM/c. The points
are plotted at equal intervals of the particleвЂ™s proper time.
217
9.10 Trajectories of photons

equation (9.32) for massive particle orbits with respect to proper time . Using
the original equation to remove the first derivative dr/d , we find that

d2 r GM h2 3h2 GM
=в€’ 2 + 3 в€’ 2 4
d2 r r cr
As we might expect, the first two terms on the right-hand side are very like
the Newtonian expressions corresponding to an inward gravitational force and a
repulsive вЂ˜centrifugal forceвЂ™ proportional to h2 . The third term is new, however,
and is also proportional to h2 but this time acts inwards. This shows that close to a
highly compact object, specifically within the radius r = 3GM/c2 , the centrifugal
force вЂ˜changes signвЂ™ and is directed inwards, thus hastening the demise of any
particle that strays too close to the object. This leads to spiral orbits of the type
shown in Figure 9.5.

9.10 Trajectories of photons
The trajectory of a photon (and of any other particle having zero rest mass) is a
null geodesic. We cannot use the proper time as a parameter, so instead we use
some affine parameter along the geodesic. Considering motion in the equatorial
plane, the equations of motion are given by the geodesic equations (9.21) and
(9.23), and we replace the r-equation (9.22) by the condition g x x = 0. Thus
Л™Л™
we have
2
Л™
1в€’ t=k (9.45)
r
в€’1
2 2
r2 в€’ r2 Л™ 2 = 0
Л™2
1в€’ t в€’ 1в€’ Л™
2
(9.46)
c
r r
r2 Л™ = h (9.47)

For photon trajectories, an analogue of the energy equation (9.32) can again be
obtained by substituting (9.45) and (9.47) into (9.46), which gives

h2 2
r + 2 1в€’
Л™ = c 2 k2
2
(9.48)
r r

Similarly, the analogue for photons of the shape equation (9.33) is obtained by
substituting h = r 2 Л™ into (9.46) and using the fact that
dr dr d h dr
= =
r2 d
d dd
218 The Schwarzschild geometry

Making the usual substitution u в‰Ў 1/r and differentiating with respect to we
find
d2 u 3GM
+ u = 2 u2 (9.49)
d2 c

It is again worth mentioning the two special cases of radial motion and motion in
a circle.

For radial motion Л™ = 0 and (9.46) reduces to
в€’1
2 2
Л™2
1в€’ t в€’ 1в€’ r2 = 0
Л™
2
c
r r
from which we obtain
2
dr
= В±c 1 в€’ (9.50)
dt r

On integrating, we have
r
ct = r + 2 ln в€’ 1 + constant outgoing photon
2
r
ct = в€’r в€’ 2 ln в€’ 1 + constant incoming photon
2
Notice that under the transformation t в†’ в€’t, incoming and outgoing photon paths
are interchanged, as we would expect. In fact for the moment the differential
equation (9.50) is more useful. In a ct r -diagram, we see that the photon
worldlines will have slopes В±1 as r в†’ (forming the standard special-relativistic
lightcone), but their slopes approach В± as r в†’ 2 . This means that they become
more vertical; the cone вЂ˜closes upвЂ™.
Our knowledge of the lightcone structure allows us to construct the вЂ˜pictureвЂ™
behind our earlier algebraic result that a particle takes infinite coordinate time to
reach the horizon; this is illustrated in Figure 9.6. The curved solid line is the
worldline of a massive particle dropped from rest by an observer fixed at r = R.
Since massive particle worldlines are confined within the forward lightcone in any
event, the closing up of the lightcones forces the worldlines of massive particles
to become more vertical as r в†’ 2 . Thus, the particle вЂ˜reachesвЂ™ r = 2 only
at t = . Further, suppose that at some point along its trajectory the particle
emits a radially outgoing photon in the direction of the observer. The tangent to
219
9.12 Circular motion of photons

Particle Observer
ct

n
oto
Ph

r = 2Вµ r=R

Figure 9.6 A radially infalling particle emitting a radially outgoing photon. The
wavy line indicates the singularity at r = 0.

the resulting photon worldline must, at any event, lie along the outward-pointing
forward lightcone at that point. This is illustrated by the broken line in Figure 9.6.
Thus, in the limit where the particle approaches r = 2 , the initial direction of
the photon worldline approaches the vertical and so the photon will be received
by the observer only at t = . Thus to an external observer the particle appears
to take an infinite time to reach the horizon.
As discussed earlier, however, the proper time experienced by a massive
particle in falling to r = 2 is finite. Moreover, dr/d does not tend to zero at this
point, so the particle has not вЂ˜run out of steamвЂ™ and presumably passes beyond
this threshold. Thus, our present coordinate system is inadequate for discussing
what happens at and within r = 2 , and our ct r -diagram is in some respects
misleading in these regions. We discuss this further in Chapter 11.

9.12 Circular motion of photons
For motion in a circle we have r = constant. Thus, from the shape equation (9.49),
we see that the only possible radius for a circular photon orbit is
3GM
r=
c2
220 The Schwarzschild geometry

Therefore a massive object can have a considerable effect on the path of a photon.
There is no such orbit around the Sun, for example, since the solar radius is much
larger than 3GM /c2 в‰€ 4 5 km, but outside a black hole there can be such an
orbit. As we shall see below, however, the orbit is not stable.

9.13 Stability of photon orbits
We can rewrite the вЂ˜energyвЂ™ equation (9.48) for photon orbits as

Л™
r2 1
+ Veff r = 2 (9.51)
h2 b
where we have defined the quantity b = h/ ck and the effective potental
1 2
Veff r = 1в€’
r2 r
In fact, by rescaling the affine parameter along the photon geodesic in such a way
that в†’ h the explicit h-dependence in (9.51) may be removed.
The effective potential is plotted in Figure 9.7, from which we see that Veff r
has a single maximum at r = 3 , where the value of the potential is 1/ 27 2 .
Thus the circular orbit at r = 3 is unstable. We conclude that there are no stable
circular photon orbits in the Schwarzschild geometry.
The character of general photon orbits is determined by the value of the
constant b. To find the physical meaning of b, we begin by using the geodesic
equation (9.45) and the energy equation (9.47) to write
Л™ в€’1/2
11 1 2
d
= = 2 2 в€’ 2 1в€’
Л™
dr r rb r r

Veff

1
27Вµ2

r

r = 2Вµ r = 3Вµ

Figure 9.7 The effective potential for photon orbits.
221
Appendix 9A: General approach to gravitational redshifts

closest
approach
r
b
П†

в€љ
Figure 9.8 The shape of a photon orbit passing a spherical mass if b > 3 3 .

Thus, for a photon orbit, as r в†’ we have
d
= В±b
r2
dr
в†’ 0 as r в†’
Assuming that , the solution to this equation is
b
r =В±
sin
which gives the equations of two straight lines with impact parameter b passing
on either side of the origin.
The nature of the orbits depends very much on the value of the impact param-
eter b. Let us first consider inward-moving photons, i.e. photons for which r is
initially decreasing. From (9.51) and Figure 9.7 we see that if 1/b2 < 1/ 27 2 ,
в€љ
so that b > 3 3 , then the orbit will have a single turning point of closest
approach and escape again to infinity. This situation is illustrated in Figure 9.8.
в€љ
If b < 3 3 , however, then the light ray will be captured by the massive body
and spiral in towards the origin. в€љ
Similar considerations hold for trajectories that start at small radii. If b > 3 3
then the photon will escape, and at infinity its straight-line path will have an impact
в€љ
parameter b. If b < 3 3 then the photon path will have a turning point, and it
will fall back towards the origin. In this case the particle does not reach infinity,
so b cannot be interpreted simply as an impact parameter. It is straightfoward to
show that if a photon is emitted from within the region r = 2 to r = 3 then the
opening angle from the radial direction for the photon to escape varies from
= 0 at r = 2 to = /2 at r = 3 .

Appendix 9A: General approach to gravitational redshifts
Consider a general spacetime with metric g in some arbitrary coordinate system
x , where x0 is a timelike coordinate and the xi are spacelike. Suppose that an
222 The Schwarzschild geometry

uR(B)
Оµ

p(B)
B

uE (A)

p(A)
A

Figure 9.9 Schematic illustration of the emission and reception of a photon.

emitter and a receiver have worldlines xE E and xR R respectively, where
E and R are the proper times of each observer. At some event A, emits a
photon with 4-momentum p A that is received by at an event B. Furthermore,
let us assume that at event A the emitter has 4-velocity uE A and that at event
B the receiver has 4-velocity uR B . This is illustrated schematically in Figure 9.9.
The energies of the photon as observed by the emitter at A and by the receiver
at B are respectively given by

E A = p A В· uE A = p A uE A
E B = p B В· uR B = p B uR B

Since in both cases E = h , the ratio of the photon frequencies is given by the
general result

p B uR B
R
= (9.52)
p A uE A
E

If we know the components of the 4-momentum p A at emission then we can
calculate the components p B at reception, using the fact that the photon travels
along a null geodesic. Since the photon 4-momentum p at any point is tangent
to this geodesic, it is parallel-transported along the path. Thus, if the photon
223
Appendix 9A: General approach to gravitational redshifts

geodesic x is described in terms of some affine parameter then

dp dx
в€’ =0
p
d d
Moreover, since p is tangent to the geodesics, we can choose the affine parameter
so that p = dx /d , in which case
dp
= pp
d
It is also worth remembering that a first integral of the equation for a photon
geodesic, which can prove very useful, is

p p =0 (9.53)

Let us now examine some special cases of the general formula (9.52). We
begin by considering the case in which both the emitter and the receiver
have fixed spatial coordinates. Thus, for i = 1 2 3 the spatial components of
their 4-velocities are
i i
dxE dxR
в‰Ў =0 в‰Ў =0
ui ui
and
E R
dE dR

Moreover, in each case, the squared length of the 4-velocity is g u u = c2 . In
our situation, this reduces to g00 u0 2 = c2 , so we find that
c
u0 = 1/2
g00

Hence the formula (9.52) reduces to

1/2
pB g00 A
=0
R
(9.54)
p0 A g00 B
E

Let us now make the additional assumption that the metric is stationary in our
chosen cooordinate system, i.e.

=0
0g

Thus, the metric components g cannot depend explicitly on the coordinate x0 .
As shown in Section 3.19, this means that the zeroth covariant component of the
tangent vector is constant along an affinely parameterised geodesic. Since the
photon 4-momentum is simply proportional to the tangent vector, this means that
224 The Schwarzschild geometry

p0 is constant along the photonвЂ™s geodesic. Thus, in this case, (9.54) reduces
further to
1/2
gA
= 00
R
(9.55)
g00 B
E

and we have recovered the result (9.14) derived earlier.

Exercises
9.1 Show that surfaces of constant t and r in the general isotropic metric (9.3) have
surface area 4 r 2 .
9.2 For the general static isotropic metric (9.4), show that the off-diagonal components of
the Ricci tensor R are zero and that the diagonal components are given by (9.8вЂ“9.11).
9.3 The Schwarzschild line element is
в€’1
2 2
ds = c 1в€’ dt в€’ 1 в€’ dr 2 в€’ r 2 d в€’ r 2 sin2 d
2 2 2 2 2
r r
By considering the вЂ˜LagrangianвЂ™ L = g x x , where the dots denote differentiation
Л™Л™
with respect to an affine parameter , calculate the connection coefficients .
Hence verify that the geodesic equations are given by (9.17вЂ“9.20).
9.4 Derive the results (9.17вЂ“9.20) using the alternative form (9.28) of the geodesic
equations.
9.5 Calculate the connection coefficients and the Ricci tensor for the general isotropic
metric (9.3). Hence prove BirkoffвЂ™s theorem.
9.6 Use BirkhoffвЂ™s theorem to show that a particle inside a spherical shell of matter
experiences no gravitational force.
9.7 Show that the вЂ˜LemaitreвЂ™ line element
2/3 2/3
4 9 9
ds = c dw в€’ dz в€’ z в€’ cw
2 2 2 2 2 2
d
9 2 z в€’ cw 2
where d 2 = d 2 + sin2 d 2 , describes the Schwarzschild geometry. Show that
observers with fixed spatial coordinates z are in free fall and had zero velocity
at infinity, and that the proper time of such observers is w.
9.8 For a general stationary spacetime with line element
ds2 = g00 x dt2 + gij x dxi dxj
show that, for a fixed emitter and receiver, the ratio of the received photon frequency
to the emitted frequency is
1/2
gx
= 00 E
R
g00 xR
E

where xE and xR are the fixed spatial coordinates of the emitter and receiver
respectively.
225
Exercises

9.9 An isolated thin rigid spherical shell has mass M and radius R. Suppose that a
small hole is drilled through the shell, so that an observer O at the shellвЂ™s centre
can observe the outside universe. Show that a photon emitted by a fixed observer
E at r = rE (where rE > R) and received by O is blueshifted by the amount
1/2
1 в€’ 2 /rE
=
O
1 в€’ 2 /R
E

9.10 Show that the quantity
p2
L =p +
2 2
sin2
where p is the 4-momentum of a particle, is a constant of motion along any
geodesic in the Schwarzschild geometry. Hence show that the particle orbits in a
Schwarzschild geometry are stably planar.
9.11 For a particle dropped from rest at infinity in the Schwarzschild geometry, find
expressions for t r and r , where t is the coordinate time and is the proper
time of the particle.
9.12 A particle is dropped from rest at a coordinate radius r = R in the Schwarzschild
geometry. Obtain an expression for the 4-velocity of the particle in t r
coordinates when it passes coordinate radius r.
9.13 A particle at infinity in the Schwarzschild geometry is moving radially inwards with
coordinate speed u0 . Show that at any coordinate radius r the coordinate velocity
is given by
2 2
2GM 1 2GM
dr
= 1в€’ 2 c2 1 в€’ 1в€’
2
c2 r
dt cr 0
в€’1/2
where 0 = 1 в€’ u2 /c2 . Determine the velocity relative to a stationary observer
0
at r, and show that this velocity tends to c as r tends to 2GM/c2 , irrespective of
the value of u0 .
9.14 Suppose that the particle in Exercise 9.13 has rest mass m0 and that it stopped at
r = r1 . If its excess energy was converted to radiation that is observed at infinity,
show that the energy released as seen by a stationary observer at r1 is

E = m0 c 2 в€’1
0

1 в€’ 2GM/ c2 r1
What is the energy released as observed at infinity? Show that this tends to 0 m0 c2
as r1 tends to 2GM/c2 .
9.15 For a particle in a circular orbit of radius r in the Schwarzschild geometry, use the
alternative form (9.28) of the geodesic equations to show that
d GM
=3
dt r
9.16 In the Schwarzschild geometry, a photon is emitted from a coordinate radius r = r2
and travels radially inwards until it is reflected by a fixed mirror at r = r1 , so
226 The Schwarzschild geometry

that it travels radially outwards back to r = r2 . How long does the round trip take
according to a stationary observer in infinity?
9.17 A photon moves in a circular orbit at r = 3 in the Schwarzschild geometry. Show
that the period of the orbit as measured by a stationary observer at this radius is
= 6 /c. What is the period of the orbit as measured by a stationary observer
infinity?
9.18 Show that a massive particle moving in the innermost stable circular orbit in the
Schwarzschild geometry has speed c/2 as measured by a stationary observer at this
radius. Hence calculate the period of the orbit as measured by the local observer.
What is the period of the orbit as measured by a stationary observer infinity?
9.19 Alice is situated at a fixed position on the equator of the Earth (which is assumed to
be spherical). In Schwarzschild coordinates t r , her worldline is described
in terms of a parameter by

t= r =R = /2 =

where and are constants and R is the coordinate radius of the EarthвЂ™s surface.
Bob is a distant stationary observer in space. Show that he will measure the orbital
speed of Alice to be v = R / . By considering the magnitude of AliceвЂ™s 4-velocity,
show that
в€’1/2
v2 GM
= 1в€’ 2 + 2
c cr
where M is the mass of the Earth. Interpret this result physically.
9.20 All massive objects look larger than they really are. Show that a light ray grazing
the surface of a massive sphere of coordinate radius r > 3GM/c2 will arrive at
infinity with impact parameter
1/2
r
b=r
r в€’ 2GM/c2

Hence show that the apparent diameter of the Sun M = 2 Г— 1030 kg R =
7 Г— 108 m exceeds the coordinate diameter by nearly 3 km.
9.21 The Hipparcos satellite can measure the positions of stars to an accuracy of 0.001
arcseconds. If it is measuring the position of a star in a direction perpendicular
to the plane of the EarthвЂ™s orbit, do Hipparcos observers need to account for the
gravitational bending of light by the Sun?
9.22 A massive particle is moving in the equatorial plane of the Schwarzschild geometry.
Show that at infinity the particle moves in a straight line with impact parameter
в€љ
b = h/ c k2 в€’ 1 .
9.23 An observer at rest at coordinate radius r = R in the Schwarzschild geometry
drops a massive particle which free-falls radially inwards. When the particle is at a
coordinate radius r = rE it emits a photon radially outwards. Find an expression for
the redshift z of the photon when it is received by the observer. Show that z в†’
as rE в†’ 2GM/c2 .
227
Exercises

9.24 Show that the geodesic equations for photon motion in the equatorial plane = /2
of the Schwarzschild geometry can be written in the form
в€’1
1 2 Л™=1 1
Л™
t= 1в€’ r2 =
Л™ в€’U r
r2 b2
bc r
where b is a constant, the dots correspond to differentiation with respect to some
affine parameter and
1 2
Ur = 1в€’
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